The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden.
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Answers
2( area of semicircle ) + (area of rectangle)
= area of circle ( r= 3.5 m ) + area of rectangle ( l= 13 m , b = 7 m )
= π r² + lb
=( 22/7 × 3.5) + ( 13 ×7 )
= 11 + 91
= 102 m²
Answer:
Perimeter of the figure is 48 m
Area of figure is 178.5 m^2
Step-by-step explanation:
From the given figure we can say the length of the figure is 20 m and the breadth of the rectangle is 7 m.
On observing the diagram, we get : -
Diameter of the semi - circle is equal to the breadth of the rectangle.
Therefore the diameter of the semi - circle is 7 m.
Then,
Radius of the semi - circle = 7 m / 2 = 3.5 m.
= > Perimeter of the figure = 2 x [ ( length of rectangle - 2 radius of semi circle ) + circumference of semi circle( excluding the diameter ) ]
= > Perimeter of the figure = 2 x [ 20 m - 2( 3.5 m ) + π( 3.5 m ) ]
= > Perimeter of the figure = 2 [ 20 m - 7 m + ( 22 / 7 x 3.5 m ) ]
= > Perimeter of the figure = 2 [ 13 m + 11 m ]
= > Perimeter of the figure = 48 m
Then,
= > Area of the figure = Area of rectangle + Area of semi circles
= > Area of figure = ( 13m x 7 m ) + 2( 1 / 2 π( 3.5 m )^2 )
= > Area of figure = 91 m^2 + 38.5 m^2
= > Area of figure = 129.5 m^2