Question

The shape of a garden is rectangular in the middle and the semi circular at the ends as shown in the diagram. find the area and perimeter of this garden (length of rectangle is 20-(3.5+3.5) meters).

Answer 1

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Length of rectangular garden = 13 m..... (given)

Radius of the semicircular end = 3.5 m

Now,

We know that 2 Semicircles = 1 circle.

Therefore,

Perimeter of the garden = 2 × length of rectangle + circumference of circle.


$= \: 2l \: + \: 2 \: \pi \: r$

=> 2 × 13 + 2 × 22/7 × 3.5

=> 26 + 22

=> 48 m ......... (ANS)

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Answer 2

Answer:

Perimeter of garden = 48 m

Step By  Step Explanation:

Given: Total length = 20 m

Diameter of semi circle = 7 m

So, Radius of semi circle = 7/2 = 3.5 m

Length of rectangular field = 20 – (3.5 + 3.5) = 20 – 7 = 13 m

Breadth of the rectangular field = 7 m

So, Area of rectangular field = l * b = 13 * 7 = 91 m^2

Area of two semi circles = 2 * (πr^2)/2

                                           = 2 * (22/7 * 3.5 * 3.5)/2

                                        = 22 * 0.5 * 3.5

                                        = 38.5 m^2

Area of garden = 91 + 38.5 = 129.5 m^2

Now Perimeter of two semi circles = 2 * πr

                                                             = 2 * 22/7 * 3.5

                                                              = 2 * 22 * 0.5 = 22 m

And Perimeter of garden = 22 + 13 + 13 = 48 m