Question

The shape of a garden is rectyangular in the midle and semicircular at the ends as shown in the diagram.Find the area and perimeter
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Answer 1

Answer:

HI BUDDY

$area \: of \: the \: figure = area \: of \: rectangle \: + \: 2 \times area \: of \: one \: semicirle \\ area = l \times b + 2 \times \ \frac{\pi {r}^{2} }{2} \\ area = l \times b + \pi {r}^{2} \\ here \: l = \: 20m \: \: \: b = 7m \: \: \: \\ r = \frac{7}{2} m \: (diameter \: of \: the \: semicircle = breadth \: of \: the \: rectangle) \\ area = 20 \times 7 + \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \\ area = 140 + \frac{77}{2} \\ area = 140 + 38.5 \\ area = 178.5 {m}^{2} \\ \\ now \\ perimeter = 2 \times length \: of \: rectangle + 2 \times circumference \: of \: \\ semicircle \\ perimeter = 2l + 2 \times \frac{2\pi \times r}{2} \\ perimeter = 2l + 2\pi \times r \\ perimeter = 2 \times 20 + 2 \times \frac{22}{7} \times \frac{7}{2} \\ perimeter = 40 + 22 \\ perimeter = 62m \\ \\ hope \: this \: helps \\ \\ please \: mark \: as \: brainliest$

Answer 2

I think it's the answer