Question

the shape of a racing track is rectangular in middle and semicircular in the ends . find the perimeter and area. ​

Answer 1

Given :-

length of the rectangular track = 35m

breadth of the rectangular track = 14m

diameter of the circular track = 14m

To Find :-

The perimeter and area of the given figure.

Solution :-

For the two circles :-

Diameter = 14 m

Radius = 14m/2 = 7m

Perimeter = 2πr

${\sf{=\:2\: \times\: {\dfrac{22}{7}}\: \times\: 7}}$

${\sf{=\:2\: \times\: 22}}$

${\sf{=\:44}}$

Therefore, perimeter of the circle = 44 m

Area = πr²

${\sf{=\:{\dfrac{22}{7}}\: \times\: 7\: \times\: 7}}$

${\sf{=\:22\: \times\: 7}}$

${\sf{=\:154}}$

Therefore, area of the circle = 154 m²

For the rectangle :-

length = 35m

breadth = 14m

Perimeter = 2(l + b)

= 2 × (35 + 14)

= 2 × 49

= 98 m

Therefore, perimeter of the rectangle = 98m

Area = l × b

= 35 × 14

= 490

Therefore, area of the rectangle = 480m²

Total perimeter of the figure = 44m + 44m + 98m

= 186 m

Total area of the figure = 154m² + 154m² + 480m²

= 788 m²

Therefore, the perimeter and area of the given figure are 186m and 788m² respectively.