Question

the shape of frustum of cone of height 21cm the radii of its two circular end are 3cm and 2cm find the capacity of the glass and curved surface area of frustum​

Answer 1

Answer:

,

Step-by-step explanation:

Answer is given in the attachment

Answer 2

The capacity of the glass is 418 cm³.

The curved surface area of frustum​ is 330.37 cm².

Step-by-step explanation:

Given : The shape of frustum of cone of height 21 cm the radii of its two circular end are 3 cm and 2 cm.

To find : The capacity of the glass and curved surface area of frustum​ ?

Solution :

The height h=21 cm

The radius are r=2 cm and R=3 cm

The slant height is $l=\sqrt{h^2+(R-r)^2}$

$l=\sqrt{21^2+(3-2)^2}$

$l=\sqrt{441+1}$

$l=\sqrt{442}$

The capacity of the frustum glass is given by,

$V=\frac{1}{3}\pi h(R^2+r^2+Rr)$

$V=\frac{1}{3}\times \frac{22}{7}\times 21(3^2+2^2+(3)(2))$

$V=22(9+4+6)$

$V=22(19)$

$V=418$

The capacity of the glass is 418 cm³.

The curved surface area of frustum​ is given by,

$CSA=\pi l(R+r)$

$CSA= \frac{22}{7}\times \sqrt{442}(3+2)$

$CSA= \frac{22}{7}\times \sqrt{442}\times 5$

$CSA= 330.37$

The curved surface area of frustum​ is 330.37 cm².

#Learn more

The slant height of a frustum of a cone is 5 cm if the difference of the radius of two circular and is 4 cm find the height of the frustum

https://brainly.in/question/7088880