Question

the shape of the top surface of a table is a trapezium 4 metre. find its area if its parallel side in 11.2 and perpendicular distance between them is 0.8 .​

Answer 1

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$area \: of \: trapezium = hieght \frac{(a \times b)}{2} \\ \leqslant = 0.8 \frac{(1\times 1.2)}{2} \\ < = \frac{0.8}{2} (2.2) \\ < = 0.4(2.2) \\ \\ \leqslant = (0.88 {m}^{2} )$

$\rule{300}{2}$

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Answer 2

Answer:

Area of trapezium =height (a×b)/2

=0.8(1 ×1.2)/2

=0.8/2(2.2)

=0.2(2.2)

=0.88²