Question

The shape of the top surface of a table is a trapezium. Find its area
if its parallel sides are 1 m and 1.2 m and perpendicular distance
between them is 0.8 m.​

Answer 1

Given,

Base i)= 1 m

Base ii)= 1.2 m

Perpendicular distance or height= 0.8 m

So,

Area of trapezium =[ {(base i)+(base ii)} / 2] *height

                              =[{(1 m)+(1.2)}/2]*0.8

                              =[(2.2)/2]*0.8

                              =1.1*0.8

                              =0.88 sq. metre

                                   

                             

Answer 2

Question :-

The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Given :-

• Shape of table = Trapezium

• Length of parallel sides = 1m and 1.2m

• Perpendicular distance = 0.8m

To find :-

• Area of trapezium?

Formula used :-

• $\dfrac{1}{2} \times (a + b) \times h$

Solution :-

• $\dfrac{1}{2} \times (1 + 1.2) \times 0.8$

• $\dfrac{1}{2} \times (2.22) \times 0.8$

• $0.88 {cm}^{2}$

Hence , the required area

⠀⠀ = ${0.88cm}^{2}$