Question

The shape of the top surface of a table is a trapezium. Find its area
if its parallel sides are l m and 1.2 m and perpendicular distance
between them is 0.8 m.​

Answer 1

$\underline{\underline{\sf{\maltese\:\:Question}}}$

• The shape of the top surface of a table is a trapezium. Find its area  if its parallel sides are 1 m and 1.2 m and perpendicular distance  between them is 0.8 m.​

$\underline{\underline{\sf{\maltese\:\:Given}}}$

• The shape of the top surface of a table is a trapezium

• Parallel sides are 1 m and 1.2 m

• Perpendicular distance  between Parallel sides is 0.8 m

$\underline{\underline{\sf{\maltese\:\:To\:Find}}}$

• Area of the top surface of table

$\underline{\underline{\sf{\maltese\:\:Answer}}}$

• Area of the top surface of table is 0.88m²

$\underline{\underline{\sf{\maltese\:\:Calculations}}}$

• Area of Top Surface = Area of Trapezium

Area of Trapezium

=  1/2 × Sum of Parallel Sides × Distance Between Them

=  1/2 × Sum of Parallel Sides × Height

As Parallel Sides are 1 m and 1.2 m

=  1/2 × (1 m + 1.2 m) × Height

=  1/2 × (2.2 m) × Height

=  1/2 × 2.2 m × Height

As Given Height is 0.8 m

=  1/2 × 2.2 m × 0.8 m

=  1/1 × 1.1 m × 0.8 m

=  1.1 m × 0.8 m

= 0.88 m²

∴ Area of the top surface of table is 0.88m²

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Answer 2

Answer:

$\huge \bf \: given$

• Parallel sides of trapezium = 1 metre and 1.2 metre
• Distance between them = 0.8 m

$\huge \bf \: to \: find$

Area of the table surface

$\huge \bf \: solution$

$\huge \boxed {a \: = \frac{1}{2} \times( sum \: of \: parallel \: side) \times distance}$

Let :-

1 m = 100 cm

1.2 m = 120 cm

0.8 m = 80 cm

$\sf \: a \: = \dfrac{1}{2} \times (100 + 120) \times 80$

$\sf \: a \: = \dfrac{1}{2} \times 220 \times 80$

$\sf \: a \: = 110 \times 80$

$\sf \: a \: = 8800 \: cm$

$\rm\: 8800 \: cm \: = 88 \: metre$

Therefore area of top surface of table 88 metre