Question

The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m​

Answer 1

Given question ::-

The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m ?

Given ::-

• Shape of surface is trapezium.

• Parallel sides are 1 and 1.2 m

• Height of trapezium is 0.8m

To find ::-

• Find the area of trapezium ?

Formula used ::-

• Area = $\dfrac{1}{2}$ × sum of ll sides × height

Solution ::-

• Parallel sides = 1 and 1.2m

• Height = 0.8m

Area of trapezium

= $\dfrac{1}{2}$ × (1 + 1.2) × 0.8

= $\dfrac{1}{2}$ × 2.2 × 0.8

= 0.88 ${m}^{2}$

__________

Hence, Area of trapezium = 0.88 ${m}^{2}$

Answer 2

Q1.The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Ans1:

Parallel sides=1m and 1.2m

height=0.8m

Area of table top==\frac{1}{2}\times\left(sum\ of\ parallel\ sides\right)\times\left(dis\tan ce\ between\ them\right)\ =

2

1

×(sum of parallel sides)×(distance between them)

=\frac{1}{2}\times\left(1+1.2\right)\ \left(0.8\right)=

2

1

×(1+1.2) (0.8)

=\frac{2.2\times0.8}{2}=

2

2.2×0.8

==\frac{2.2\times0.8}{2}=

2

2.2×0.8

==\frac{2.2\times0.8}{2}=

2

2.2×0.8

=0.88\ m^20.88 m

2

Explanation:

ans.0.88.m.