Question

The shape of the top surface of a table is a trapezium Find its area if its parallel sides are 1m and 1.2 m and perpendicular distance between them is 0.8m .​

Answer 1

One parallel side of the trapezium (a) = 1 m

One parallel side of the trapezium (a) = 1 mAnd second side (b) = 1.2 m and

One parallel side of the trapezium (a) = 1 mAnd second side (b) = 1.2 m andheight (h) = 0.8 m

One parallel side of the trapezium (a) = 1 mAnd second side (b) = 1.2 m andheight (h) = 0.8 mArea of top surface of the table = 1/2 (a + b) h

One parallel side of the trapezium (a) = 1 mAnd second side (b) = 1.2 m andheight (h) = 0.8 mArea of top surface of the table = 1/2 (a + b) h= 1/2 ( 1+ 1.2 ) 0.8

One parallel side of the trapezium (a) = 1 mAnd second side (b) = 1.2 m andheight (h) = 0.8 mArea of top surface of the table = 1/2 (a + b) h= 1/2 ( 1+ 1.2 ) 0.8= 1/2 x 2.2 x 0.8 = 0.88

One parallel side of the trapezium (a) = 1 mAnd second side (b) = 1.2 m andheight (h) = 0.8 mArea of top surface of the table = 1/2 (a + b) h= 1/2 ( 1+ 1.2 ) 0.8= 1/2 x 2.2 x 0.8 = 0.88Area of top surface of the table is 0.88 m^2

Answer 2

$\huge \bold \red{s} \bold \blue{o} \bold \green{l} \bold \pink{u} \bold \orange{t} \bold \red{i} \bold \blue{o} \bold \green{n}$

Area =

$\frac{1}{2}$

(sum of its two parallel sides ) × height

$= \frac{1}{2} \times (1 + 1.2)m \times 0.8m$

$\huge \bold \blue{ = 0.88 {m}^{2}}$