Question

The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1m and 1.2m and perpendicular distance between them is the 0.8m .?​

Answer 1

Given :

• The shape of the top surface of a table is a trapezium.

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To Find :

• Area of trapezium ?

$~$

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SolutioN :

• Let us assume that, the area of trapezium be x.

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${\bf{\dag}}$ Formula Used :

$\qquad\star~{\underline{\boxed{\pmb{\sf{Area~of~ trapezium~=~\dfrac{1}{2}~×~ (sum~ of~ parallel ~sides)~×~height}}}}}$

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${\bf{\dag}}$ According to the Question :

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$\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(1~+~1.2\bigg)~×~0.8}}$

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$\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(2.2\bigg)~×~0.8}}$

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$\qquad{\sf:\implies{Area~=~\dfrac{12}{20}~×~\dfrac{8}{10}}}$

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$\qquad{\sf:\implies{Area~=~\cancel\dfrac{176}{200}}}$

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$\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area~=~0.88 }}}}}}$★

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Hence,

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$\qquad$ ∴ The area of trapezium is 0.88m².

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Answer 2

Answer:

Given :

The shape of the top surface of a table is a trapezium.

~

To Find :

Area of trapezium ?

~

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SolutioN :

Let us assume that, the area of trapezium be x.

~

{\bf{\dag}}† Formula Used :

\qquad\star~{\underline{\boxed{\pmb{\sf{Area~of~ trapezium~=~\dfrac{1}{2}~×~ (sum~ of~ parallel ~sides)~×~height}}}}}⋆

Area of trapezium =

2

1

× (sum of parallel sides) × height

Area of trapezium =

2

1

× (sum of parallel sides) × height

~

{\bf{\dag}}† According to the Question :

~

\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(1~+~1.2\bigg)~×~0.8}}:⟹Area =

2

1

(1 + 1.2) × 0.8

~

\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(2.2\bigg)~×~0.8}}:⟹Area =

2

1

(2.2) × 0.8

~

\qquad{\sf:\implies{Area~=~\dfrac{12}{20}~×~\dfrac{8}{10}}}:⟹Area =

20

12

×

10

8

~

\qquad{\sf:\implies{Area~=~\cancel\dfrac{176}{200}}}:⟹Area =

200

176

~

\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area~=~0.88 }}}}}}:⟹

Area = 0.88

Area = 0.88

★

~

Hence,

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\qquad ∴ The area of trapezium is 0.88m².

~

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