Question

The shape of top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m ​

Answer 1

Answer:

Now,

Given the top surface is in the shape of

trapezium.

Area of the top surface

= Area of trapezium

$\bold{ \frac{1}{2} \times (sum \: of \: parralel \: sides) \times height}$

$\huge \bold{ \underline{given}}$

Length of Parallel sides is 1m and 1.2 m

$\bold{\therefore \: a = 1m \: and \: b = 1.2m}$

& Height= perpendicular distance between parallel sides.

$\bold{h = 0.8m}$

$\bold{area = \frac{1}{2} (a + b) \times h}$

$\bold{area = \frac{1}{2} \times (1 + 1.2) \times 0.8}$

$\bold{ = \frac{1}{2} \times 2.2 \times 0.8}$

$\bold{ = \frac{1}{2} \times \frac{22}{10} \times \frac{8}{10} }$

$\bold{ = \frac{22 \times 4}{100} }$

$\bold{ = \frac{88}{100} }$

$\bold{ = 0.88 {m}^{2} }$

$\bold{ \therefore \: area \: of \: table \: surface \: of \: table = 0.88 {m}^{2} }$

Answer 2

Answer:

Area=1/2* Sum of parallel sides*perpendicular distance

Area=1/2(1+1.2)(0.8)

Area=0.88m2.

Step-by-step explanation:

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