The shapes of the hockey court and the
shooting range are square and triangle
respectively. Both of the courts have a
common vertex that coincide with the
centre of circular camp. The construction
of the shooting range is such that the
angle to centre is 900. The radius of the
circular camp is 180 metres. On the basis
of given information answer the following
questions.
Answers
Given : (complete Question is )
The areas allotted for a hockey court and a shooting range of NCC TRAINING CAMP
The shapes of the hockey court and the shooting range are square and triangle respectively. Both of the courts have a common vertex that coincide with the centre of circular camp. The construction of the shooting range is such that the angle to centre is 90°. The radius of the circular camp is 180 metres.
To Find :
1) What is the area allotted to shooting range ?
(a) 12, 600 m² (b) 22, 000 m² (c) 16,200 m² (d) 16, 880 m²
2) What is the area allotted to hockey court ?
(a) 12, 600 m² (b) 22, 000 m² (c) 20, 000 m² (d) 16, 200 m²
3) What is the area of training camp.
(a) 101736 m² (b) 32400 m² (c) 16200 m² (d) 20000 m²
4) If the management of NCC TRAINING Camp likes to allot space for some more sports, how much area is available to them?
(a) 85, 536 m² (b) 95, 800 m² (c) 60, 040 m² (d) 69,336 m²
Solution :
OA = OB = Radius = 180 m
angle = 90°
Area of shooting range = (1/2) * 180 * 180 = 16200 m²
OD = Radius = 180 m
OE = 180/√2 = 90√2 m
Area of Hockey court = (90√2)² = 16200 m²
area of training camp. = π(180)² = 3.14(180)² = 1,01,736 m²
area is available = 1,01,736 - 16200 - 16200 = 69,336 m²
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