Question

the sheet of metal has dimensions 56cm by 33 it is melted and recast into discs of the same thichness and radius 7cm how many discs will be cast

Answer 1

The area of sheet =56*33=1848
The area of discs=π7*7=154
The no of discs that could be casted=1848/154=12
Hence,12 discs could be casted if there is no loss of metal

Answer 2

Answer:

• Total 12 discs will be cast

Step-by-step explanation:

Given,

• A sheet of metal has dimensions 56cm by 33 cm.
• It is melted down and recast into discs of the same thickness and radius 7 cm

To find:

• How many discs will be cast?

Solution:

As, here we are given a sheet of metal whose dimensions are 56 cm and 33cm and a disc of radius 7cm. So, we will Find area of both a sheet of metal and disc.

Area of Rectangular sheet = Length × Breadth

Where,

• Length = 56 cm
• Breadth = 33 cm

$\sf \mapsto56 \times 33$

$\sf \mapsto1848 \: {cm}^{2}$

• Area of metal sheet is 1848 cm²

Now,

Area of disc = πr²

$\sf \mapsto \dfrac{22}{7} \times {(7)}^{2}$

$\sf \mapsto \dfrac{22} { \cancel{7}} \times \cancel{ 7 }\times 7$

$\sf \mapsto22 \times 7$

$\sf \mapsto154 \: {cm}^{2}$

• Area of disc is 154 cm²

We have get the required area of Metal sheet and discs:

Number of discs that will be make:

$\sf \mapsto \dfrac{1848}{154}$

$\sf\mapsto 12 \: discs$

Hence,

• Total 12 discs will be cast.