Question

The ship has coordinates (2,3) the equation of the other line is x+y=2 find the shortest distance from the ship to the line.​

Answer 1

Answer:

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Step-by-step explanation:

x + y = 2

x + y – 2 = 0

Distance from (2, 3) to the line x + y – 2 = 0

= (2 + 3 – 2)/√(1^2 + 1^2)

= 3/√(1 + 1)

= 3/√2

= (3 × √2)/(√2 × √2)

= (3√2)/2 units.

Answer: (3√2)/2 units

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Answer 2

Line ->x+y-2=0 and Point- (p) (2,3)

$distance = | \frac{ax + by + c}{ \sqrt{ {a {}^{2} + b}^{2} } } |$

a=1,b=1 and c= -2, x=2 and y= 3

$| \frac{1 \times 2 + 1 \times 3 - 2}{ \sqrt{ {1 {}^{2} + 1}^{2} } } |$

$| \frac{3}{ \sqrt{2} } |$

3/√2(√2/√2)

(3/√2)√2 units

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