Social Sciences, asked by dnilay, 5 months ago

The shire has implemented a contact tracing program to reduce the spread of SARs-CoV-2. They estimate that in the last four weeks, they had an average of 6250 confirmed cases of COVID-19 per week, and recorded 200 total deaths due to with known SARS-CoV-2 infection, on average within 3days of symptoms onset. Sample collection for testing typically occurred the day after symptom onset. Household contact tracing was very successful: 90% of household contacts were reached and quarantined on the same day that the case was isolated. Community contact tracing was more challenging . Only 35% of community contacts were identified and quarantined, normally 2days after the case was isolated. Shire epidemiologists believe that about 0.75% of infected die of COVID-19 and that on average, individuals live with 3other people and report 2 to 4 contacts outside of the household in the last two weeks. What percentage of infections in the community were detected? What is the estimated reproductive number in the Shire after his contact tracing program is implemented?

Answers

Answered by ItsBlueberry
1

Answer:

.The actual distance traversed by Ranjit from home to school

The actual distance traversed by Ranjit from home to school= AB + BC + CD

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutes

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metres

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to school

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to schoolDisplacement

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to schoolDisplacement1000 metres 40 metres = 0.66 metres/second

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to schoolDisplacement1000 metres 40 metres = 0.66 metres/secondVelocity =

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to schoolDisplacement1000 metres 40 metres = 0.66 metres/secondVelocity =Total time

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to schoolDisplacement1000 metres 40 metres = 0.66 metres/secondVelocity =Total time25 minutes 60 seconds

The actual distance traversed by Ranjit from home to school= AB + BC + CD= 500 m + 700 m + 300 m = 1500 m.Total time from home to school = 8 minutes + 11 minutes + 6 minutes = 25 minutesRanjit's displacement from home to school, AD = 1000 metresThus, Ranjit's velocity when going from home to schoolDisplacement1000 metres 40 metres = 0.66 metres/secondVelocity =Total time25 minutes 60 secondsRanjit's speed while going to s

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