Question

the shopkeeper buy two article for rupees 40000 he sold first article at a profit of 28% and second at a loss of 12% he het 8% loss on whole transaction find CP of each article and selling price of second article​

Answer 1

Answer:

Let C

1

be the cost price of the first article and C

2

be the cost price of the second article.

Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.

We know, C

1

+C

2

=600.

The first article was sold at a profit of 22%.

∴, the selling price of the first article =C

1

+(

100

22

)C

1

=1.22C

1

The second article was sold at a loss of 8%.

∴, the selling price of the second article =C

2

−(

100

8

)C

2

=0.92C

2

.

The total selling price of the first and second article =1.22C

1

+0.92C

2

.

As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.

∴,1.22C

1

+0.92C

2

=C

1

+C

2

=600

As C

1

+C

2

=600,C

2

=600−C

1

. Substituting this in 1.22C

1

+0.92C

2

=600, we get

1.22C

1

+0.92(600−C

1

)=600

or 1.22C

1

−0.92C

1

=600−0.92×600

or 0.3C

1

=0.08×600=48

or C

1

=

(0.3)

48

=160.

If C

1

=160, then C

2

=600−160=440.

The item that is sold at loss is article 2. The selling price of article 2=0.92×C

2

=0.92×440=404.80..

Step-by-step explanation:

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Answer 2

Answer:

Chemistry is the scientific study of the properties and behavior of matter. It is a natural science that covers the elements that make up matter to the compounds composed of atoms, molecules and ions: ...