Question

The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 48 hours.

Answer 1

Radius of the shorter hand=4 cm

Distance covered in 1 hour is the circumference of the circle

Circumference of the circle= 2*π*r

=2*22/7*4=25.14 cm approx

=25.14*48=1206.72 cm

Radius of the longer hand =6cm

Circumference of the circle=2*π*r

=2*22/7*6=37.71 cm approx

=37.71*48=1810.08cm

Total distance= 1206.72+1810.08=3016.80 cm

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Answer 2

Answer:

Given :

Length of short hand = 4 cm

Length of long hand = 6 cm

We know short hand make 1 revolution in 12 hours while long hand in 1 hour.

Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm

Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm

Total distance travelled = 32 π cm +  576 π cm = 608 π cm

Therefore ,  sum of distances travelled by their tips in two day is 608 π cm.