Question

the short and long hands of a clock are 4cm and 6cm long resp.find the sum of distances travelled ny their tips in 2 days

Answer 1

Answer:

180979.2 or 180979 approx

Step-by-step explanation:

2 days =60mins*24hrs*2 days=2880 no. of revolutions each

   circumference of long hand=2*pie*r

                                                 =2*22/7*6=37.7

                                  similarly =2*22/7*4=25.14

therefore total distance covered by both in two days is (37.7+25.14)*2880

                                                                                         =180979.2cm

           

Answer 2

Answer:

Given :

Length of short hand = 4 cm

Length of long hand = 6 cm

We know short hand make 1 revolution in 12 hours while long hand in 1 hour.

Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm

Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm

Total distance travelled = 32 π cm +  576 π cm = 608 π cm

Therefore ,  sum of distances travelled by their tips in two day is 608 π cm.