The short and long hands of a clock are 4cm and 6cm long respectively. find the sum of distances travelled by their tips in 48hours.
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2×3.14×4×4=32×3.14
2×3.14×6×48=576×3.14
(32+576)3.14
608×3.14=190912cm
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Answer:
Given :
Length of short hand = 4 cm
Length of long hand = 6 cm
We know short hand make 1 revolution in 12 hours while long hand in 1 hour.
Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm
Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm
Total distance travelled = 32 π cm + 576 π cm = 608 π cm
Therefore , sum of distances travelled by their tips in two day is 608 π cm.
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