Math, asked by bablu7930, 1 year ago

The short and long hands of a clock are 4cm and 6cm long respectively. find the sum of distances travelled by their tips in 48hours. ​

Answers

Answered by Venugopa
2

2×3.14×4×4=32×3.14

2×3.14×6×48=576×3.14

(32+576)3.14

608×3.14=190912cm


bablu7930: thx broo
Answered by Anonymous
2

Answer:

Given :

Length of short hand = 4 cm

Length of long hand = 6 cm

We know short hand make 1 revolution in 12 hours while long hand in 1 hour.

Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm

Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm

Total distance travelled = 32 π cm +  576 π cm = 608 π cm

Therefore ,  sum of distances travelled by their tips in two day is 608 π cm.

Similar questions