Question

the short and long hands of the clock are 4cm and 6cm respectively find the sum of distances travelled by their trip in 2 days

Answer 1

measure of the long hand = 6 cm
measure of the short hand = 4 cm

Let's first see the distance they travel in a day..
From 1 to 12 I.e. one circle I.e. 360°
It passes twice a day..
i.e. 360 • 2 ...(360×2)
= 720
One day = twice
Two days = 4 times..
Therefore, we get...
720 × 2. *OR*. 360 × 4
Therefore, we get 14,40..
Ans = 1440 cm

Answer 2

Answer:

Given :

Length of short hand = 4 cm

Length of long hand = 6 cm

We know short hand make 1 revolution in 12 hours while long hand in 1 hour.

Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm

Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm

Total distance travelled = 32 π cm +  576 π cm = 608 π cm

Therefore ,  sum of distances travelled by their tips in two day is 608 π cm.