The short hands of a clock are 4cm and 6cm long respectively. Find the sum of distance travelled by their tips in 48 hours
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The tips cover circular paths.
The hour hand covers 4 complete circles in 2 days (48 hours)
Distance = 2 x 22/7 x 4 x 4 = 100.57 cm
The minute hand covers = 48 Circles in 2 days (Each hour = 1 circle)
Distance = 2 x 22/7 x 6 x 48 = 1810.23 cm
Total distance = 100.57 + 1810.23 = 1910.8 cm
Hope it helps you
The hour hand covers 4 complete circles in 2 days (48 hours)
Distance = 2 x 22/7 x 4 x 4 = 100.57 cm
The minute hand covers = 48 Circles in 2 days (Each hour = 1 circle)
Distance = 2 x 22/7 x 6 x 48 = 1810.23 cm
Total distance = 100.57 + 1810.23 = 1910.8 cm
Hope it helps you
AaravSamrat:
Hlo
anushka
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Answer:
Given :
Length of short hand = 4 cm
Length of long hand = 6 cm
We know short hand make 1 revolution in 12 hours while long hand in 1 hour.
Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm
Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm
Total distance travelled = 32 π cm + 576 π cm = 608 π cm
Therefore , sum of distances travelled by their tips in two day is 608 π cm.
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