The shortest wavelength for lyman series is 912 A.U. Find shortest wavelengths for paschen an
brackett series in hydrogen atom
Answers
Answer:
if α,β are the roots of the q.ef(x)= ax2 + bx + c = 0 then the q.e whose roots are
i) the squares of the roots off(x) = 0 isf(x−−√) = 0
ii) the cubes of the roots of f(x) = 0 isf(x−−√3) = 0
the equation that formed by squaring each of the equationx2 + 2x − 4 = 0 is
answer key
a
solution
f(x) = x2 + 2x − 4
a = 1 b = 2 c = −4
f(x−−√) = 0
a3x2 + (b3 − 3abc)x + c3 = 0
x2 + (8 − 3(1)(2)(−4))x + (−4)3 = 0
x2 − 32x + If α,β are the roots of the Q.Ef(x)= ax2 + bx + c = 0 then the Q.E whose roots are
i) the squares of the roots off(x) = 0 isf(x−−√) = 0
ii) the cubes of the roots of f(x) = 0 isf(x−−√3) = 0
The equation that formed by squaring each of the equationx2 + 2x − 4 = 0 is
Answer Key
A
Solution
f(x) = x2 + 2x − 4
a = 1 b = 2 c = −4
f(x−−√) = 0
a3x2 + (b3 − 3abc)x + c3 = 0
x2 + (8 − 3(1)(2)(−4))x + (−4)3 = 0
x2 − 32x + 64 = 0
Chapter
04_Quadratic equations