Question

the shunt required for 10%of main current to be sent through the moving coil galvanometer of resistance 99ohm will be

Answer 1

Here the shunt resistance must be 11ohm

Answer 2

The shunt required will be 11 ohm.

We know that potential difference across galvanometer is equal to the potential difference across the shunt so we have

igG=(i-ig)S........(1)   where we have

ig is current through galvanometer.

i is main current

G is resistance of galvanometer.

S as resistance of shunt.

Now according to question ig=1/10i G=99 ohm

Substituting values in equation (1) we have;-

(1/10)i*99=(i-i/10)S

(1/10)i*99=(9/10)iS cancelling i and 1/10 both sides we have

99=9S so S=11 ohm

Hence resistance of shunt is 11 ohm.