Question

the SI on a certain sum for 3years at 8% per annum is rs.96 more than the SI on the same sum for 2 years at 9% per annum.Find the sum.​

Answer 1

Answer:

1600

Step-by-step explanation:

Let the sum of money =x.

rate=8%

Time=3 years

So,

WE KNOW,

SI=P×R×T/100.

SO,

SI=x×8×3/100.

so si=24x/100.

IN 2ND CASE.

si=x*2*9/100.

so SI=18x/100.

so Acc.TO ques.

24x/100=18x/100+96.

24x/100 - 18x/100=96.

6x/100=96.

6x=9600.

x=9600/6.

x=1600.

so amount is 1600.

Answer 2

$\huge\mathfrak\red{Question:}$

The simple interest on a certain sum for 3 years at 8% per annum is Rs. 96 more than the simple interest on the same sum for 2 years at 9% per annum. Find the sum.

$\huge\mathfrak\green{Solution:}$

Let the required sum be Rs. x. Then,

SI on Rs. x at 8% p.a. for 3 years

$= rs.( \frac{x \times 8 \times 3}{100} ) = rs .\:\frac{6x}{25}$

SI on Rs. x at 9% p.a. for 2 years

$rs.( \frac{x \times 9 \times 2}{100} ) = rs. \frac{9x}{50}$

Hence,

$\frac{6x}{25} - \frac{9x}{50} = 96$

$(12x - 9x) = 96 \times 50$

$3x = 4800$

$x = \frac{4800}{3}$

$x = 1600$

Hence, the required sum is Rs. 1600