The SI on certain sum of money for 23 month at the rate of 7% per annum exceeds the SI on the same sum at 7% per annum for 19 month by Rs. 672 . then find the sum ?
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Answer:
Let the principal be P
And in question rate of interest is same 7%
Time in ist case is 1-11/12=23/12
In 2nd case time is 1-7/12=19/12
And the difference given is 672
So P*7*23/1200……1st case si
P*7*19/1200……………….2nd case si
(P*7*23/1200)-(P*7*19/1200)=672
7P(23/1200-19/1200)=672
7P(4/1200)=672
7P(1/300)=672
7P/300=672
P/300=96
P=300*96=28800
SO principal is 28800 in both case ans
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Answer:
28800 is answer for both cases
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