The SI unit of thermal conductivity is
a) JS-1m
-1K
-1 b) JSm-1K
c) JSm-1K
-1 d) JS-1mK
Answers
Answered by
0
Answer:
W/(m⋅K) is the true answer.
Answered by
0
Answer:
JS/m⋅1K
Explanation:
watts per
Units. In the International System of Units (SI), thermal conductivity is measured in watts per meter-kelvin (W/(m⋅K)). Some papers report in watts per centimeter-kelvin (W/(cm⋅K)). In imperial units, thermal conductivity is measured in BTU/(h⋅ft⋅°F).
And W = JS
So.... Answer is : JS/m⋅1K
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