Question

The side a,b,c of a right triangle where C is hypotension are circumscribing a circle prove that radius is circle given r= a+b-c/2​

Answer 1

Answer:

Let the circle touches sides AB,BC and CA at F,D and E respectively where AB=c,BS=a and AC=b

Length of the tangents drawn from an external point are equal.

AE=AF

BD=BF

CE=CD=r

b−r=AF

a−r=BF

So, AB=AF+BF

c=b−r+a−r

c=a+b−2r

2r=a+b−c

r=

2

a+b−c

Answer 2

Answer:

r=a+b-c/2 because :

Step-by-step explanation:

It is given in question and I don't give my brain efforts on things that are already solved.

Brainliest me