Math, asked by jokkerr2, 5 months ago

The side AB BC & CA of triangle ABC touch a circle with
centre O & radius r at P, Q & R respectively.
Prove that: A (ABC) = 1/2 P(ABC) × r

Answers

Answered by MrHellForYou

2

Step-by-step explanation:

REFER TO THE PHOTO ABOVE

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