Math, asked by ayushmishra9, 1 year ago

The side AB of a parallelogram ABCD is produced to X and the bisector of angle CBX meet DA produced and DC produced at E and F respectively . prove that DE =DF=BA +BC

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Answered by musalikreyhan

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The side AB of a parallelogram ABCD is produced to X and the bisector of angle CBX meets DA produced and DC produced to E and F respectively. Prove that DE=DF=BA+BC

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