the side ac of a triangle abc is produced to E such that CE=1/2 AC. if D is the mid point of BC and ED prodeuce to meet AB at F and CP and DA are drawn parallel to BA the prove that FD=1/3FE.
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BC and DQ.They're drawn parallel to BA. ... If D is the midpoint of BC and ED produced to meet AB at F and CP and DQ are parallel to AB prove that FD = 1/3 FE.
In triangle ABC, the side AC is produced
In triangle ABC, the side AC is produced
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