Math, asked by MRTyagi0715, 28 days ago

The side AC of a triangle ABC is produced to the point E so that CE = 1/2 AC. D is the mid point of BC and ED produced meets AB at F . Lines through D and C are drawn parallel to AB which meets AC at point P and EF at point R respectively . Prove that : 1. 3DF = EF 2. 4CR = AB​

Answers

Answered by hk7899213
0

Answer:

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