Question

The side bc of a triangle abc is produced such that d is on ray bc. The bisector of angle a meetsbc in l . Prove that angle abc+angle acb=2×angle alc

Answer 1

Answer:

To Prove ABC + ACD = 2A C  

AL in the angle bisector of A, so let BAL = LAC = x

Then, using exterior angle property

∠ALC = x  + z          ..(1)

Similarly  

 ∠ACD= 2x +  z                           ..(2)

Hence from (1) and (2), we get  

ABC + ACD = 2ALC

(i.e.)

 ( z ) + (2x +  z ) = 2(x + z )

∠ABC+∠ACB=2∠ALC

HENCE PROVED

Answer 2

Answer:

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