the side BC of a triangle ABC is produced to a point D. the bisector of angle A meets side BC in L. if angle ABC=30°and angle ACD=115° find angle ALC
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ABC + ACD+ACL= 180
30+115+ACL= 180
ACL=180-145
ACL=35
so, answer is 35 degree
I hope you will be understand my answer
30+115+ACL= 180
ACL=180-145
ACL=35
so, answer is 35 degree
I hope you will be understand my answer
gupta3079:
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