The side BC of ΔABC has been produced to a point D, such that ∠ACD = 140. If ∠B = 2/5 × ∠A, then find ∠A.
Options...
A.) 90°
B.) 80°
C.) 110°
D.) 100°
Answers
Answered by
1
A.) 90. Degree
B.) 80 dégrée
B.) 80 dégrée
Answered by
0
Answer:
∠BAC+∠ABC=∠ACD(Exterior angle sum property)
∠BAC+2/5∠BAC=140°
(5∠BAC+2∠BAC)/5=140°
7∠BAC/5=140°
7∠BAC=700°
∠BAC=700°/7
∠BAC=100°
Option D
Similar questions