Question

the side BC of ∆ABC is produced to D, the bisector of angle A meet BC at E. prove that angle ABC + angle ACD= 2 angle AEC.​

Answer 1

Answer:

2<ALC

Step-by-step explanation:

InΔABL

let∠BAL=a&∠BA=b

exterior∠ALC=∠BAL+∠LBA

=a+b

InΔABC

ALbisect∠BAC&∠AC=a

exterior∠ACD=∠BAC+∠ABC

=2a+b

=∠ABC+∠ACo

=b+(2a+b)

=2a+2b

=2(a+b)

=2∠ALC