Question

the side BC of an equilateral triangle ABC is extended to D such that BC=CD prove that AD2 = 3AC square

please give me answer it's very urgent​

Answer 1

In the right angled triangle ADC, we have AD^2 = AC^2 - DC^2 by using Pythagoras theorem

= BC^2- DC^2 since ABC is equilateral AC=BC

= (2DC)^2 - DC^2 altitude AD bisects the base in an equilateral triangle

= 4DC^2 -DC^2

= 3DC^2

Hence AD^2 = 3 DC^2

PLS MARK BRAINLIEST

& MARK

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