Question

The side BC of triangle ABC has been produced to a point D such that angle ACD= 140°. If angle B =3/5 angle A, then find angle A.​

Answer 1

Answer:

angle A = 175/2 degree = 87.5 degree

Step-by-step explanation:

By angle sum property of triangle,

∠A + ∠B +∠C = 180°

=> ∠A + 3/5 of ∠A + (180° - 140°) = 180°

=> 8/5 ∠A + 40° = 180°

=> 8/5 ∠A  = 180° - 40°

=> 8/5 ∠A  = 140

=> ∠A  = 140 * 5/8

=> ∠A  = 175/2°

or ∠A  = 87.5°

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