Question

The side BC of triangle ABC has been produced to a point D, such that angle ACD=140°. If angle B = 2/5, then find the angle A​

Answer 1

Answer:

$extrior \: angle = sum \: of \: two \: interior \: opposite \: angles \\ so \\ 2x + 5x = 140 \\ 7x = 140 \\ x = 20 \\ angle \: a = 5 \times 20 = 100$

Answer 2

Answer:

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Step-by-step explanation:

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