Question

The side BC of triangle ABC is a produced to D. The bisector of angle ABC and angle ACD meet at a point E. If angle BAC = 68º, then the measure of angle BEC is -

Answer 1

Answer:

∠E

Step-by-step explanation:

By exterior angle theorem,

∠ACD = ∠A + ∠B

∠ACD = 68° + ∠B

1/2∠ACD = 34° + 1/2∠B

34° = 1212∠ACD - ∠EBC (i)

Now,

In ΔBEC

∠ECD = ∠EBC + ∠E

∠E = ∠ECD - ∠EBC

∠E = 1/2∠ACD - ∠EBC (ii)

From (i) and (ii), we get

∠E = 34°

Hope it Helps!!!