Question

The side bc of triangle ABC is produced to point D . The bisector of angle ABC and angle ACD meet at point e. If angle BAC=68,then find the measure of angle BEC​

Answer 1

Step-by-step explanation:

=>By exterior angle theorem,

=>∠ACD = ∠A + ∠B

=>∠ACD = 68o + ∠B

=> ∠ACD = 34o +  ∠B

=>34o =  ∠ACD - ∠EBC ------(i)

Now, In

=>∠ECD = ∠EBC + ∠E

=>∠E = ∠ECD - ∠EBC

=>∠E = ∠ACD - ∠EBC --------(ii)

From (i) and (ii), we get

=>∠E = 34

         hope it helps mark as brilliant.

Answer 2

Answer:

Hope this helps dude

Step-by-step explanation:

By exterior angle theorem,

=>∠ACD = ∠A + ∠B

=>∠ACD = 68o + ∠B

=> ∠ACD = 34o +  ∠B

=>34o =  ∠ACD - ∠EBC ------(i)

Now, In

=>∠ECD = ∠EBC + ∠E

=>∠E = ∠ECD - ∠EBC

=>∠E = ∠ACD - ∠EBC --------(ii)

From (i) and (ii), we get

=>∠E = 34