Math, asked by Nicole5702, 7 days ago

the side by of a square abcd is produced to any point e prove that
Ae2=2bc.be+ce2

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Answered by ac8804
0

Answer:

Ex 6.5, 13 D and E are points on the sides CA and CB respectively of a triangle ABC right angled at C. Prove that AE2 + BD2 = AB2 + DE2 Given : triangle ABC , right angled at C Two points D and E are on the sides CA and CB To prove: AE2 + BD2 = AB2 + DE2 Proof : Let us join the points D with E and B . And point E with A Using Pythagoras theorem (Hypotenuse)2 = (Height)2 + (Base)2 Here , ACE is a …

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