Math, asked by Rawala6420, 27 days ago

The side measurement of the wall of the Green House is 9m. Find the cost of the glass required for the walls of the Green House, if the cost of 1m2 glass is AED 12.

Answers

Answered by bhagyashreechowdhury
4

Given:

The side measurement of the wall of the Green House is 9m. Find the cost of the glass required for the walls of the Green House, if the cost of 1m2 glass is AED 12.

To find:

Find the cost of the glass required for the walls of the Green House, if the cost of 1 m² glass is AED 12.

Solution:

Considering it to be a cubical shaped greenhouse

The length of the side of the wall, a = 9 m

Since we need to find the cost of the glass required for the walls of the Greenhouse, so, we have to first find the area of the four walls or the lateral surface area of the Greenhouse.

Finding the L.S.A. of the Greenhouse:

We know,

\boxed{\bold{Lateral \:Surface \:Area \:of\:a\:cube = 4a^2}}

By substituting the value of a = 9 m in the above formula, we get

The area of the walls of the Greenhouse is,

= Lateral Surface Area of the cubical greenhouse

= 4a²

= 4 × 9²

= 4 × 81

= 324 m²

Finding the cost of the glass required:

If the cost of 1 m² of glass is AED 12

Then,

The total cost of 324 m² of glass will be,

= AED 12/m² × 324 m²

= AED 3888

Thus, the cost of the glass required for the walls of the Greenhouse is → AED 3888.

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