Question

The side of a cube is double the length of the cuboid .the breadth and height of cuboid are half of its length.find ratio of C.S.A of cube to cuboid

Answer 1

length = 2 × breadth
height = 1/2 × length 
height = 1/2 × 2 × breadth 
height = breadth 
volume of cuboid = l × b × h
2 b × b × b
answer \: = 2{b}^{3}answer=2b3 
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Answer 2

Lenght of cuboid=
$l$
Breadth and height of cuboid =
$\frac{l}{2}$
CSA of cuboid =

$2(lb + bh + hl) \\ 2(l \times \frac{l}{2} + \frac{l}{2} \times \frac{l}{2} + \frac{l}{2} \times l) \\ = 2( \: \frac{ {l}^{2} }{2} + \frac{ {l}^{2} }{4} + \frac{ {l}^{2} }{2} ) \\ = \frac{ {5l}^{2} }{2}$


side of cube=
$2l$
CSA of cube =
$6 {side}^{2} \\ = 6 \times {(2l)}^{2} \\ = 6 \times 4 \times {l}^{2} \\ = 24 {l}^{2}$
Ratio=
$\frac{24 {l}^{2} }{5 {l}^{2} } \times 2$
48:5