Question

The side of a cube is measured by a Vernier calliper,
whose 10 divisions of the vernier scale are equal to
8 divisions of main scale. If the main scale reads
10 mm and second division of vernier scale
coincides with one of the main scale division, then
the volume of the cube in appropriate significant
figures is (take 1 MSD = 1 mm)
(1) 2.76 cm3
(2) 1.03 cm3
(3) 1.12 cm3
(4) 1.00 cm​

Answer 1

Answer:

2.76 cubic cm .

Explanation:

10 VSD = 8 MSD

VSD =$\frac{8}{10}$ MSD

Least count = 1 MSD - 1 VSD = $1 -\frac{8}{10}=0.2$

Main scale reading=10mm=1cm

Vernier coincidence= 2nd division

Vernier scale reading= $0.2\times 2=0.4$

Total reading=1+0.4=1.4

Volume=$1.4\times 1.4 \times 1.4$=2.76

So. Option 1 is true

Hence Volume of cube is 2.76 cubic cm .

Answer 2

Answer:

The ans will be first option...i.e. 2.76 cm³