Question

The side of a cuboid are in the ratio 6:4:3.Surface area of its faces is 432 sq.m.Find its sides?

Answer 1

Solution :

Let l , b and h are length, breadth

and height of the cuboid respectively,

l : b : h = 6 : 4 : 3 [ given ]

Let l = 6x ,

b = 4x ,

h = 3x ,

Surface area = 432 sq m

2( lb + bh + lh ) = 432

=> 2[ 6x * 4x + 4x *3x +3x *6x ] = 432

=> 24x² + 12x² + 18x² = 432/2

=> 54x² = 216

=> x² = 216/54

=> x² = 4

=> x = 2

Therefore ,

l = 6x = 6 × 2 = 12 m

b = 4x = 4 × 2 = 8 m

h = 3x = 3 × 2 = 6 m

••••

Answer 2

Answer:

{ l=12m, b=8m, h=6m }

Step-by-step explanation:

Let the side of cuboid = LiB and H Ratio of side, f / b / b = 6 / t / 3

perp=6x

b = 4x

h = 3x

S Dutt / t,t,0 area of cuboid vartheta = 2(db + bh + bd) 2.5jm underline =432 n + 1

=2(6xx+44x3x+34*3x+34*3x)=43x =21x^ 2 +12x^ 2 +18x^ 2 =216

54x ^ 2 = 216 H^ 2 = 2JK-4^ 2 5/y +

mathcal H ^ 2 =12J^ 2

x = 2

now, L=6A=6X2=12 m b=4x=4X2=8m

L=3x=3X2=6m