the side of a cuboid are in the ratio 6 ratio 4 ratio 3 surface area of its face is 432m find its side
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let the ratio be x
so
length becomes 6x
breadth becomes 4x
height becomes 3x
now given total surface area of cuboid is
432 cm
total surface area of cuboid is
2 [ (6x)(4x) + (4x)(3x) + (3x)(6x) ] = 432
2 [ 24(x^2) + 12(x^2) + 18(x^2) ] = 432
2 [ 54(x^2) ] = 432
108 (x^2) = 432
x^2 = 4
x = 2
so length is 6(2) = 12
breadth is 4(2) = 8
height is 3(2) = 6
so
length becomes 6x
breadth becomes 4x
height becomes 3x
now given total surface area of cuboid is
432 cm
total surface area of cuboid is
2 [ (6x)(4x) + (4x)(3x) + (3x)(6x) ] = 432
2 [ 24(x^2) + 12(x^2) + 18(x^2) ] = 432
2 [ 54(x^2) ] = 432
108 (x^2) = 432
x^2 = 4
x = 2
so length is 6(2) = 12
breadth is 4(2) = 8
height is 3(2) = 6
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