Question

the side of a polygon are 9 in numbers what would be the sum of its internal angles​

Answer 1

Given,

Number of sides of the given polygon $=9$.

We know that, sum of interior angles of a polygon $=(n-2)\times180^{0}$.

Where, '$n$' is number of sides.

So, sum of interior angles in given $9$ sided polygon $=(9-2)\times180^{0}$

$=7\times180^{0}$

$=1260^{0}$.

Hence, sum of interior angles in the given polygon $=1260^{0}$.

Answer 2

sum of  internal angles​ of a polygon is 1260° if there are 9 sides

Given : A polygon with 9 sides  

To Find : sum of polygon's  internal angles​

Solution:

A polygon with  n number of sides

sum of Internal angles of the polygon is given by (n  - 2) * 180°

Here Given that sides are 9

Hence n = 9

sum of polygon's  internal angles​ = ( 9 - 2) * 180°

=> sum of polygon's  internal angles​ = 7 * 180°

=> sum of polygon's  internal angles​ = 1260°

sum of its internal angles​ of polygon is 1260° when sides are 9

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