The side of a rectangle are in the ratio 3:2.if its permeter is 50th,f find the its sides.
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Let length be l=3x
Let breadth be b= 2x
Given: Perimeter = 50 cm(maybe)
Perimeter = 2(l + b)
[substituting value of perimeter in RHS and vaue of length and breadth on LHS.]
50cm= 2 (3x + 2x)
50cm= 10x
therefore, x = 5cm
hence, length = 3x =3*5cm=15cm
breadth=2x=2*5cm=10cm
jaivinpanchmatia:
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Here is your solution
Given :-
The ratio of length and breadth of the given rectangle is 3:2
Let the length and breadth be 3x and 2x .
perimeter of the rectangle = 2 (length + breadth)
=>50=2( 3x+ 2x)
=>50/2=5x
=>5=x
Length =3x=3×5=15 unit
Breadth =2x=2×5=10 unit
hope it helps you
Given :-
The ratio of length and breadth of the given rectangle is 3:2
Let the length and breadth be 3x and 2x .
perimeter of the rectangle = 2 (length + breadth)
=>50=2( 3x+ 2x)
=>50/2=5x
=>5=x
Length =3x=3×5=15 unit
Breadth =2x=2×5=10 unit
hope it helps you
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