Question

the side of a rectangle are in the ratio 3:2 . if the area is 486sqm find the cost of fencing it at 40 per metre.

Answer 1

Step-by-step explanation:

Let the dimensions of the rectangle be:-

• Length → 3x

• Breadth → 2x

Now, the formula for finding the area of Rectangle = length × breadth

→ Area of the rectangle = 486 m²

→ (length × breadth) = 486

→ 3x × 2x = 486

→ 6x² = 486

→ x² = 486/6

→ x = √81

→ x = 9

Therefore, dimensions of the rectangle are:-

• length = 3x = 3×9 = 27 m

• breadth = 2x = 2×9 = 18 m

Now, the formula for finding the perimeter of the rectangle = 2(length + breadth)

→ Perimeter of the rectangle = 2(length + breadth)

→ Perimeter of the rectangle = 2 (27 + 18)

→ Perimeter of the rectangle = 2 × 45 m

→ Perimeter of the rectangle = 90 m

• Cost of Fencing = ₹ 40/m

→ Total Cost = ₹ (40/m × 90m)

→ Total Cost = ₹ 3600

Therefore, the total cost of Fencing at ₹ 40/m is equal to ₹ 3600.

Please mark as “Brainliest Answer”.....

Answer 2

• Cost of fence of rectangle is 3600.

Step-by-step explanation:

Given:-

• Sides of rectangle are in radio of 3:2.
• Area of rectangle is 486 m².
• Cost of fencing is 40 per meter.

To find:-

• Cost of fencing the rectangle.

Solution:-

Let, Length of rectangle be 3x.

And breadth of rectangle be 2x.

Area of rectangle = length × breadth

➝ 3x × 2x = 486

➝ 6x² = 486

➝ x² = 486/6

➝ x² = 81

➝ x = √81

➝ x = 9

length = 3x = 3×9 = 27 m.

breadth = 2x = 2×9 = 18 m.

Perimeter of rectangle = 2(length + breadth)

➝ 2×(27 + 18)

➝ 54 + 36

➝ 90

We know,

Fence and perimeter are same. So,

Fence of rectangle = 90 m

1 m = 40

90 = 40 × 90

➝ 3600

Therefore

Cost of fencing of rectangle is 3600.